Optimal. Leaf size=571 \[ -\frac{4 a^2 e \left (a e^2 (2 C d-B e)-c d \left (2 C d^2-e (3 B d-4 A e)\right )\right )-x \left (A c \left (-7 a^2 e^4+12 a c d^2 e^2+3 c^2 d^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right )}{8 a^2 \left (a+c x^2\right ) \left (a e^2+c d^2\right )^3}+\frac{\tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )+a \left (-3 a^2 c d e^4 (11 C d-10 B e)+3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)+c^3 d^5 (C d-2 B e)\right )\right )}{8 a^{5/2} \sqrt{c} \left (a e^2+c d^2\right )^4}-\frac{a \left (-a B e^2+2 a C d e-2 A c d e+B c d^2\right )-x \left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right )}{4 a \left (a+c x^2\right )^2 \left (a e^2+c d^2\right )^2}+\frac{e^3 \log \left (a+c x^2\right ) \left (a e^2 (2 C d-B e)-c d \left (4 C d^2-e (5 B d-6 A e)\right )\right )}{2 \left (a e^2+c d^2\right )^4}-\frac{e^3 \left (A e^2-B d e+C d^2\right )}{(d+e x) \left (a e^2+c d^2\right )^3}-\frac{e^3 \log (d+e x) \left (a e^2 (2 C d-B e)-c d \left (4 C d^2-e (5 B d-6 A e)\right )\right )}{\left (a e^2+c d^2\right )^4} \]
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Rubi [A] time = 1.92477, antiderivative size = 566, normalized size of antiderivative = 0.99, number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {1647, 1629, 635, 205, 260} \[ \frac{x \left (A c \left (-7 a^2 e^4+12 a c d^2 e^2+3 c^2 d^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right )+4 a^2 e \left (-a e^2 (2 C d-B e)-c d e (3 B d-4 A e)+2 c C d^3\right )}{8 a^2 \left (a+c x^2\right ) \left (a e^2+c d^2\right )^3}+\frac{\tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )+a \left (-3 a^2 c d e^4 (11 C d-10 B e)+3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)+c^3 d^5 (C d-2 B e)\right )\right )}{8 a^{5/2} \sqrt{c} \left (a e^2+c d^2\right )^4}-\frac{a \left (-a B e^2+2 a C d e-2 A c d e+B c d^2\right )-x \left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right )}{4 a \left (a+c x^2\right )^2 \left (a e^2+c d^2\right )^2}-\frac{e^3 \log \left (a+c x^2\right ) \left (-a e^2 (2 C d-B e)-c d e (5 B d-6 A e)+4 c C d^3\right )}{2 \left (a e^2+c d^2\right )^4}-\frac{e^3 \left (A e^2-B d e+C d^2\right )}{(d+e x) \left (a e^2+c d^2\right )^3}+\frac{e^3 \log (d+e x) \left (-a e^2 (2 C d-B e)-c d e (5 B d-6 A e)+4 c C d^3\right )}{\left (a e^2+c d^2\right )^4} \]
Antiderivative was successfully verified.
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Rule 1647
Rule 1629
Rule 635
Rule 205
Rule 260
Rubi steps
\begin{align*} \int \frac{A+B x+C x^2}{(d+e x)^2 \left (a+c x^2\right )^3} \, dx &=-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}-\frac{\int \frac{-\frac{c \left (A \left (3 c^2 d^4+9 a c d^2 e^2+4 a^2 e^4\right )-a d^2 \left (a C e^2-c d (C d-2 B e)\right )\right )}{\left (c d^2+a e^2\right )^2}-\frac{2 c e \left (A c d \left (3 c d^2+a e^2\right )-a \left (c d^2 (3 C d-4 B e)+a e^2 (C d-2 B e)\right )\right ) x}{\left (c d^2+a e^2\right )^2}-\frac{3 c e^2 \left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x^2}{\left (c d^2+a e^2\right )^2}}{(d+e x)^2 \left (a+c x^2\right )^2} \, dx}{4 a c}\\ &=-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (2 c C d^3-c d e (3 B d-4 A e)-a e^2 (2 C d-B e)\right )+\left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )}+\frac{\int \frac{\frac{c^2 \left (A \left (3 c^3 d^6+12 a c^2 d^4 e^2+33 a^2 c d^2 e^4+8 a^3 e^6\right )-a d^2 \left (5 a^2 C e^4-6 a c d e^2 (2 C d-3 B e)-c^2 d^3 (C d-2 B e)\right )\right )}{\left (c d^2+a e^2\right )^3}+\frac{2 c^2 e \left (3 A c d \left (c d^2+3 a e^2\right )-a \left (a e^2 (5 C d-4 B e)-c d^2 (C d-2 B e)\right )\right ) x}{\left (c d^2+a e^2\right )^2}+\frac{c^2 e^2 \left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x^2}{\left (c d^2+a e^2\right )^3}}{(d+e x)^2 \left (a+c x^2\right )} \, dx}{8 a^2 c^2}\\ &=-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (2 c C d^3-c d e (3 B d-4 A e)-a e^2 (2 C d-B e)\right )+\left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )}+\frac{\int \left (\frac{8 a^2 c^2 e^4 \left (C d^2-B d e+A e^2\right )}{\left (c d^2+a e^2\right )^3 (d+e x)^2}+\frac{8 a^2 c^2 e^4 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )}{\left (c d^2+a e^2\right )^4 (d+e x)}+\frac{c^2 \left (3 A c \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+a \left (3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)-3 a^2 c d e^4 (11 C d-10 B e)+c^3 d^5 (C d-2 B e)\right )-8 a^2 c e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) x\right )}{\left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}\right ) \, dx}{8 a^2 c^2}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{\left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (2 c C d^3-c d e (3 B d-4 A e)-a e^2 (2 C d-B e)\right )+\left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )}+\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}+\frac{\int \frac{3 A c \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+a \left (3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)-3 a^2 c d e^4 (11 C d-10 B e)+c^3 d^5 (C d-2 B e)\right )-8 a^2 c e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) x}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^4}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{\left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (2 c C d^3-c d e (3 B d-4 A e)-a e^2 (2 C d-B e)\right )+\left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )}+\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}-\frac{\left (c e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )\right ) \int \frac{x}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^4}+\frac{\left (3 A c \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+a \left (3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)-3 a^2 c d e^4 (11 C d-10 B e)+c^3 d^5 (C d-2 B e)\right )\right ) \int \frac{1}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^4}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{\left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a \left (B c d^2-2 A c d e+2 a C d e-a B e^2\right )-\left (A c \left (c d^2-a e^2\right )+a \left (a C e^2-c d (C d-2 B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^2 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (2 c C d^3-c d e (3 B d-4 A e)-a e^2 (2 C d-B e)\right )+\left (A c \left (3 c^2 d^4+12 a c d^2 e^2-7 a^2 e^4\right )+a \left (3 a^2 C e^4-2 a c d e^2 (6 C d-7 B e)+c^2 d^3 (C d-2 B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )}+\frac{\left (3 A c \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+a \left (3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)-3 a^2 c d e^4 (11 C d-10 B e)+c^3 d^5 (C d-2 B e)\right )\right ) \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )}{8 a^{5/2} \sqrt{c} \left (c d^2+a e^2\right )^4}+\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}-\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right ) \log \left (a+c x^2\right )}{2 \left (c d^2+a e^2\right )^4}\\ \end{align*}
Mathematica [A] time = 0.817795, size = 498, normalized size = 0.87 \[ \frac{\frac{2 \left (a e^2+c d^2\right )^2 \left (a^2 e (B e-2 C d+C e x)-a c \left (A e (e x-2 d)+B d (d-2 e x)+C d^2 x\right )+A c^2 d^2 x\right )}{a \left (a+c x^2\right )^2}+\frac{\left (a e^2+c d^2\right ) \left (a^2 c e \left (e (A e (16 d-7 e x)-2 B d (6 d-7 e x))+4 C d^2 (2 d-3 e x)\right )+a^3 e^3 (4 B e-8 C d+3 C e x)+a c^2 d^2 x \left (2 e (6 A e-B d)+C d^2\right )+3 A c^3 d^4 x\right )}{a^2 \left (a+c x^2\right )}+\frac{\tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )+a \left (3 a^2 c d e^4 (10 B e-11 C d)+3 a^3 C e^6+a c^2 d^3 e^2 (13 C d-20 B e)+c^3 d^5 (C d-2 B e)\right )\right )}{a^{5/2} \sqrt{c}}-4 e^3 \log \left (a+c x^2\right ) \left (a e^2 (B e-2 C d)+c d e (6 A e-5 B d)+4 c C d^3\right )-\frac{8 e^3 \left (a e^2+c d^2\right ) \left (e (A e-B d)+C d^2\right )}{d+e x}+8 e^3 \log (d+e x) \left (a e^2 (B e-2 C d)+c d e (6 A e-5 B d)+4 c C d^3\right )}{8 \left (a e^2+c d^2\right )^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.076, size = 2159, normalized size = 3.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21416, size = 1494, normalized size = 2.62 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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